How do I count alpha and numeric characters in a text file? C++?

Question

I know I'll have to use isalpha and isdigit functions but I have no idea how to employ those along with reading the text file. Would I have to read each individual character in? And how would I do that? Also how could I ask the user to input a single character and count how many times that character appears in the text file?

Answer 1

This is my approach:

#include

#include

#include

using namespace std;



void count(const string& strFile, int& alpha, int& digits)

{

ifstream is(strFile.c_str());

char c; // Declare a character

if (is.good()) {

while(!is.eof()) {

is >> c; // read in one character at a time

if (isdigit(c)) {

++digits;

}

else if (isalpha(c)) {

++alpha;

}

}

}

}

int main()

{

int a = 0, d = 0;

count("football.txt", a, d);

cout << "football.txt contains " << a << " alpha character and " << d << " digits!" << endl;

return 0;

}

Answer 2

A general information:



1. take some indicators, int al=0, int nu=0, char ch="character by user",int count=0.

2. read each character until any space, comma or full stop is encountered.

3. if ,in between that, characters lie between alphabetic range of ascii table , increase al by one (al++),

4. if characters lie between numeric range of ascii table, increase nu by one (nu++),

5. and keep comparing each character with "ch" and if it matches , increase the count by one (count++).





This is a very good exercise.

Answer 3

A map is a great choice for this problem. If you're not familiar with the map container, here's an opportunity for you to learn about it. You can do something like this:



#include

#include

#include

#include