Doubt in input-output streams in C++.?

Question

int main()
{
char a;
cout<<"Enter a text: ";
while(a!='\n')
{
cin.get(a);
cout< }

On executing this code in C++ compiler, the output is :
Enter a text: abcdef
abcdef

My question is "When we give cout<
Hope you understood my question...

Thanks in advance.

Answer 1

standard input is line buffered by default. Until you press enter, no data is transferred to your program, regardless of how you're reading it - character by character or line by line.



It's usually possible to switch to unbuffered input (which you seem to want), but it requires OS-specific calls, such as tcsetattr()/stty on Unix or _getch() on Windows, or a specialized console library such as curses.

Answer 2

The unformatted get member function works like the >> operator with two exceptions. First, the get function includes white-space characters, whereas the extractor excludes white space when the ios::skipws flag is set (the default). Second, the get function is less likely to cause a tied output stream (cout, for example) to be flushed.



A variation of the get function specifies a buffer address and the maximum number of characters to read. This is useful for limiting the number of characters sent to a specific variable, as this example shows:



main()

{

char a[10];

cout << " Type a line terminated by carriage return\n>";

cin.get( a, 10 );

cout << ' ' << a;

}

In this example, you can type up to 9 characters and a terminating character. Any remaining characters can be extracted later

Answer 3

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Answer 4

You should specify the size of string.



Eg. char a[10];



you can now read 9 charector string.



It can really solve your problem.