C++ Compiler error, Cin and Cout do not work?

Question

What is wrong with this basic group of code?

#include "stdafx.h"
#include

void main ()

{
int score;
std::cout<<"What is the score? "< std::cin>>score>>std::endl;
}

COMPILER ERROR: http://pastebin.com/eudrAnbH

Answer 1

I'll try to explain the error message:



It is flagged for the line "std::cin>>score>>std::endl;" and it says, trimming it to the essentials:



"binary '>>' : no operator found which takes a left-hand operand of type istream while trying to match the argument list 'istream, overloaded-function'"



The "overloaded function" in this case is std::endl (it is an IO manipulator, all of which are, physically, defined as functions - you can call std::endl(std::cout); on a line by itself ). Operator << (insertion into a stream) can take IO manipulators as its right-hand arguments, but operator >> (extraction from stream) cannot.



The compiler could not find a version of operator >> that would take std::endl (or, in fact, any overloaded function) as its argument on the right, and that's what the error says (and, to make it a little confusing, it gives the complete list of all possible versions of operator>> that take an istream on the left)



Incidentally, my compiler also flags "void main" as an error:

test.cc:3:12: error: '::main' must return 'int'

This is because "void main" is illegal in C++ and must be written as "int main". However, your compiler was smart enough to guess that you meant "int main" there. It could not guess what did you mean by cin >> endl, though.

Answer 2

The last line in main() is incorrect.



std::cin>>score>>std::endl;



... should be replaced by:



std::cin>>score;

std::cout<


--



[Note:] Also, it would be easier if you declared the namespace by placing the line:



using namespace std;



... after including . Then, you could refer to cout, cin and endl without all those std:: namespace qualifiers.

Answer 3

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Answer 4

Why do you have '>>std::endl' at the end of your std::cin command? Get rid of that and try compiling again.

Answer 5

Not sure, but I suspect this:



std::cin>>score>>std::endl;

}



Can't input to std::endl.



Hope that helps.

Answer 6

std::endl is for output only.



You might call it "write-only memory" :-)