How do you print out a specified number of a certain symbol in C programming language?

Question

If I ask the user, "How many '^' symbols would you like to print out?" and they respond, "6", how can I program it to print out "^^^^^^".

Obviously the number they enter could vary, so I dont want you to just say "printf("^^^^^^");"

Answer 1

Hmm... yet, so some distance as i be conscious of, the only perfect numbers between a million and 1000 are 6, 28, 496. the perfect numbers are below 10 in case you make the main of the selection of unsigned long long.

Answer 2

A for loop is one way:

for (int i = 0; i < numberToOutput; i++)

   printf("^");



Another way would be to define a string that's larger than the entry you allow and printf() only a certain number of items from the string.

char tmpstr[1024];

memset(&tmpstr, '^', 1024);

printf("%*s", numberToOutput, tmpstr);



Here's the printf() function, and I used the "*" width specifier which allows you to pass it to the function call.

http://www.cplusplus.com/reference/clibrary/cstdio/printf/

Answer 3

something like this (Not a C programmer, consider as pseudo code):



int userInput;

string outputtoprint = "";



for(i=userInput; i > 0; i--){

outputtoprint += "^";

}

printf(outputtoprint);

Answer 4

With a "for" loop.