C programming, source code question?

Question

I have this pieces from a program and i need to figure if there are any errors here... if so can you tell me why? i'm trying to study for an upcoming test and i need this for practice and understand why. Anyone? Thanks

a) int *number; /*This has a problem because the point has to be defined right?*/
printf ("%d\n", *number);

b) float *realPtr;
long *integerPtr;
integerPtr = realPtr;

c) int * x, y;
x=y;

d) char s[] = "this is a character array";
int count;
for ( ; *s != '\0' ; s++) /*the for loop need the {} right??*/
printf("%c " , *s);

e) short *numPtr, result;
void *genericPtr = numPtr;
result = *genericPtr + 7;

f) float x= 19.34;
float xPtr = &x;
printf ("%f\n", xPtr);

g) char *s;
printf("%s\n", s);

Answer 1

a) Yes, number doesn't point anywhere. You can fix this by doing:



int *number;

int n = 5;



number = &n;

printf("%d\n", *number);



b) That doesn't work at all. (float *)s point to floats. (long *)s point to longs. (float **)s point to (float *)s.



c) x = &y;



d) You can't increment arrays like you can with pointers. The program can be written as:



#include



int main()

{

char s[] = "this is a character array";

char *sp;



for(sp = s; *sp != '\0'; ++sp)

printf("%c ", *sp);

return 0;

}



e) You can't dereference a (void *) since it has no defined size. numPtr doesn't point anywhere.



f) xPtr isn't a pointer, it's a float. You shouldn't store addresses in floats. float *xPtr = &x; and printf("%f\n", *xPtr); or printf("%p\n", xPtr);



g) s doesn't point anywhere.

Answer 2

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Answer 3

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