segmentation fault with ccsm in ubuntu(linux)?

Question

which opening compiz config setting manager(ccsm) via terminal it comes for a second and it vanishes,and says segmentation fault what should i do?

Answer 1

A segmentation fault occurs when a program attempts to access a memory location that it is not allowed to access, or attempts to access a memory location in a way that is not allowed (for example, attempting to write to a read-only location, or to overwrite part of the operating system). <-- wikpedia



It can be caused by bugs in software, driver or even with some hw problems.

First thing you should do is update/patch your box (via terminal as root or sudo) apt-get update (fetches new package index from repos), apt-get dist-upgrade (updates all packages, removes some if it has too).

Reboot.



If that fails try running memtest to check health of your ram, after that there is always gdb (gnu debuger) which may allow you to pinpoint the problem.



Take care

Answer 2

How To Change The Settings Of The Ubuntu 11.04 Unity Desktop With CompizConfig Settings Manager

http://www.makeuseof.com/tag/change-settings-ubuntu-unity-compizconfig-settings-manager/



Alternatively if you can live without the Unity Desktop you can downgrade from Compiz 0.9.4 to Compiz 0.8.6 which is more stable

http://www.webupd8.org/2011/05/how-to-downgrade-to-compiz-086-in.html



CompizConfig Settings Manager (CCSM)

http://wiki.compiz.org/CCSM



CompizPlugins

http://wiki.compiz.org/CompizPlugins



PluginsMain

http://wiki.compiz.org/PluginsMain



PluginsExtra

http://wiki.compiz.org/PluginsExtra





LUg.

Answer 3

Ccsm Ubuntu

Answer 4

You can try uninstalling and reinstalling Compiz. You can do this through System - Administration - Synaptic Package Manager. Type in the search window Compiz. Right click on Compiz and opt for complete removal. Next again type Compiz in the search window and mark it for installation and click apply.

Answer 5

Your argv argument announcement could be char **argv or char *argv[] quite than char *argv. In different words: int important (int argc, char **argv){ //Parameter examine if (argc < 2){ printf("incorrect variety of enter parameters.nUsage %s report", argv[0]); return EXIT_SUCCESS; } return EXIT_SUCCESS; }

Answer 6

it also occurs

when u give more values to store in an array

that is more than u declare for that array