Adding dict in Python?

Question

Forgive me if this is a repeat question, I seem to be having problems with the website.

Anyway, I have a homework question:
Assume there is a variable, album_artists , that is associated with a dictionary that maps albums to performing artists. Write a statement that inserts the key/value pair: "Live It Out" / "Metric" .

my solution is very simple:

album_artists["live it out"] = "Metric"

However, the program keeps telling me the answer is wrong, and so I have no idea how to solve this, solutions?

Answer 1

Take the list 4 5 88 5 4 9 8 9 Now, make it into pairs, with the index recorded as the second element: (4 0) (5 1) (88 2) (5 3) (4 4) (9 5) (8 6) (9 7) Next, sort by the first element of each pair, yielding: (4 4) (4 0) (5 3) (5 1) (8 6) (9 7) (9 5) (88 2) Scan the list, removing the duplicates. They are now TOGETHER, because they have been sorted together, so you only need to look at the first two elements. Always take the element with the lowest index number. After this step: (4 0) (5 1) (8 6) (9 5) (88 2) Sort by the SECOND element of each pair (the added index element): (4 0) (5 1) (88 2) (9 5) (8 6) Display each first element: 4 5 88 9 8 ================================== Memory usage: number elements * 2, or O(n) Time usage: sort is O(n log n), two sorts and two scans of n elements:, or O(n log n)

Answer 2

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Answer 3

Metric Live It Out

Answer 4

using dict.update to insert a single item creates unnecessary dict that just got dumped away immediately. The correct way, is as you have stated:



album_artists["Live It Out"] = "Metric"



perhaps you should pay attention to the capitalization.

album_artists["live it out"] = "Metric"

is different from

album_artists["Live It Out"] = "Metric"

Answer 5

Technically your solution is perfectly valid. You could also use the "update" method, e.g.:



album_artists.update( {"live it out": "metric} )