A variable declared at the start of an if clause's block will be in scope:?

Question

A variable declared at the start of an if clause's block will be in scope:

A. Only within the if clause's block, including any nested if statements
B. Within the if clause's block and the blocks of any else clauses in the same if-else or if-else-if statement.
C. Within the if clause's block, but not within any nested if statements
D. Anywhere in the method, following the variable's declaration

Answer 1

It depends on which language you are using. In C/C++ there will be an opening bracket after the if and before the declaration of the variable. The variable will remain in scope until the corresponding closing bracket. This includes nested if statements, unless another variable with the same name is declared within a nested block. Any else keyword will be the start of a new scope in which the previously declared variable will be out of scope.



In Basic, however, the end of an if block is signalled by an endif keyword, and the else, if there is one, is in the middle. In this case the variable declared at the start of the if will be in scope through the else block until the corresponding endif.

Answer 2

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Answer 3

B i guess

Answer 4

A