how to read in file name and size in a c program?

Question

Im creating an archive program.. I've created the archive and it can read in files, however in order to extract the files i need to be able to read in the file name and size.. any suggestions on how to do this..

Answer 1

What I currently read is this:

a) you read a list of files from a given path and you are able to archive the files into an archive file

b) you need the file name and size in order to extract the files.

c) you do NOT want to use the file sizes and file names from the directory you archived the files from.

If this is the correct understanding then I propose the following solution:

You have to make file name and file size part of the archive:

you can determine the file size like this:

#include

#include



int main () {

FILE * pFile;

long lSize;

size_t result;



pFile = fopen ( "myfile.bin" , "rb" );

if (pFile==NULL) {fputs ("File error",stderr); exit (1);}

else {

// obtain file size:

fseek (pFile , 0 , SEEK_END);

lSize = ftell (pFile);

fclose(pFile);

}

return 0;

}

Answer 2

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Answer 3

There's no portable way to read a directory in C (or C++ for that matter). In Unix-like operating systems, you can use opendir() and readdir(). There's an example here:

http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=11775&lngWId=3



Windows is messier. From C, you must use the Win32 APIs. The runtime library has some of the Unix-style I/O functions, but not opendir/readdir. The Win32 functions to use are FindFirstFile, FindNextFile(), and FindClose(). The following page gives a sample.

http://msdn.microsoft.com/en-us/library/windows/desktop/aa365200%28v=vs.85%29.aspx



That works as-is compiled as a C program in Visual Studio, but not in GNU GCC for windows (MinGW). You'll have to remove the header and recode the string handling to work on a non-MS compiler. As you can see from the source code, MS doesn't want you to use standard C.

Answer 4

The stat() system call will return data including the file size.



You need to use directory operations to find file names in the directory.

Use opendir(), readdir(), closedir()

Answer 5

Why do not you purely study the completed document into an array of personality strings? Then only print the call at a given random index. provided that the traditional call is way less then 20 characters, it really is purely about (1000x20) 20K of memory required, and a lot swifter get admission to.